Question

3sin theta-sin3theta/3cos theta+cos3 theta
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Answer 1

Answer:

Let theta =a

We have to find

(3 Cos a+cos 3a)/(3sina-sin3a)

=(3 cosa+4cos^3a-3cosa)/(3sina-3sina+4sin^3a)

=4cos^3a/4sin^3a

=tan^3a

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