Question

(3sin²19° + 3sin² 71°) /(5cos² 36° + 5 cos² 54°)

is equal to:

(A) 1
(B) 0
(C) 5/3

(D) 5/3

Answer 1

Option B is correct.


3sin²19° + 3sin² 71°/5cos² 36° + 5 cos² 54°


3(sin²19° + sin² 71°/ 5(cos² 36° + cos² 54°)


3 sin²90° / 5 cos²90°


3 ×1 / 5 × 0


[ Sin 90° = 1 & cos 90° = 0]


3 /0


0

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Hope this will help you......

Answer 2

(3sin^2 19° + 3 sin^2 71° ) / ( 5cos^2 36° + 5cos^2 54° )

= 3 ( cos^2 71° + sin^2 71°) / 5( sin^2 54° + cos^2 54°)

= 3/5