Question

3sin²30+cot²45+5cos²45
3cosec²60+2sec²30-5tan²46​

Answer 1

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3 sin2 30° + 2 tan2 60° -5 cos2 45°

= 3x (1/2)2 + 2(3)2 - 5(1/5)2

= (3×1/4) + (2×3) - (5×1/2)

= 3/4 + 6 - 5/2

= 3+24-10/4

= 27-10/4 = 17/4

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Answer 2

Answer:

$\huge \frac{3sin²+30+cot²45+5cos²45}{3cosec²60+2sec²30-5tan²46}$