Math, asked by rajeshchauhanrc956, 11 months ago

(3sin43/cos47)2-cos37×cosec53/tan5×tan25×tan45×tan65×tan85​

Answers

Answered by shreya628455
1

Answer:

here is the answer

Step-by-step explanation:

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Answered by devsenamishra02
2

Answer:

8

Step-by-step explanation:

(3sin43/cos47)²-cos37cosec53/tan5tan25tan45tan65tan85

=[3sin43/cos(90-43)]²-cos37cosec53/1

=(3sin43/sin43)²-cos37*1/sin53

=9 - cos37*1/sin(90-37)

=9-cos37*1/cos37

=9-1

=8

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