Math, asked by babikly, 1 day ago

3SInA-2CosA=0 , find 1) cot^2 a- cosec^2 a. 2) cos a+sina / sina - cos a pls give genuine answere or else your account will be reported​

Answers

Answered by sahityareddy710
0

Answer:

1. cot^2 a - cosec^2 a = -1

2. (cos a + sin a)/( sin a - cos a) = -(sec2a + tan2a)

Step-by-step explanation:

1.

cot^2 a - cosec^2

cos^2 a / sin^2 a - 1/ sin^2 a ( cot a = cos a/sin a) (cosec a = 1/sina)

after the lcm,

(cos^2 a - 1)/sin^2 a ( sin^2 a + cos^2 a = 1

cos^2 - 1 = - sin^2 a)

-sin^2 a/ sin^2 a = -1

2.

(cos a + sin a)/(sin a - cos a)

rationalising the denominator,we get

(cos a + sin a)^2/sin^2 - cos^2

(cos^2 + sin^2 + 2sinacosa)/sin^2 - cos^2

(1 + sin2a)/-cos2a

-(sec2a + tan2a)

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