3sinA +4cosA=5 find value of tanA
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hello,3sinA+ 4cosA=5squaring both sides,9sin2A + 16cos2B + 24sinAcosA = 25........................(1)4sinA - 3cosA = xsquaring both sides,16sin^2A + 9cos^2A – 24sinAcosA = x^2 …............(2) Add eqns. 1) and 2)9 + 16 = x^2x^2 = 25x = +5 and x = -5
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