√3sina+cosa= hello please answer it to me
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Answered by
2
√3sinA = cosA
= sinA/cosA = 1/√3
= TanA = 1/√3
=> A = tan-¹(1/√3)
=> A = 30°
= sinA/cosA = 1/√3
= TanA = 1/√3
=> A = tan-¹(1/√3)
=> A = 30°
abhi178:
correct ot
no option :/
Answered by
9
√3sina + cosa = 0
2{ √3/2 sina + 1/2 cosa } = 0
2{ sin60°.sina + cos60°.cosa } = 0
use, cosA.cosB +sinA.sinB = cos(A-B)
2cos(a - 60°) = 0
cos(a - π/3) = 0 [ 60° = π/3 in radian ]
a - π/3 = (2n +1)π/2
a = π/3 + (2n + 1)π/2
a = nπ + 5π/6 = (6n +5)π/6
2{ √3/2 sina + 1/2 cosa } = 0
2{ sin60°.sina + cos60°.cosa } = 0
use, cosA.cosB +sinA.sinB = cos(A-B)
2cos(a - 60°) = 0
cos(a - π/3) = 0 [ 60° = π/3 in radian ]
a - π/3 = (2n +1)π/2
a = π/3 + (2n + 1)π/2
a = nπ + 5π/6 = (6n +5)π/6
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