Question

3t+1/16-2t-3/7=t+3/8+3t-1/14

Answer 1

3*t-(2*t)+1/16-(3/7)=t+3*t+3/8-(1/14)

3*t-(2*t)-t-(3*t)+1/16-(3/7)-(3/8)+1/14=0

3*t-2*t-t-3*t+1/16-3/7-3/8+1/14=0

-3*t-75/112=0

-3*t=75/112

t=75/112/(-3)

t=  -25/112

Answer 2

Solving for $t$. 

$3t+ \frac{1}{16} -2t- \frac{3}{7} = t+ \frac{3}{8} +3t- \frac{1}{14}$
$3t-2t+ \frac{1}{16} - \frac{3}{7} = t+3t+ \frac{3}{8} - \frac{1}{14}$
$\frac{1}{16} - \frac{3}{7} +3t-2t = \frac{3}{8} - \frac{1}{14} +t+3t$
$- \frac{41}{112} +t = \frac{17}{56} +4t$
Transposing $- \frac{41}{112}$ to RHS and $4t$ to LHS. 
$t-4t = \frac{17}{56} + \frac{41}{112}$
$-3t = \frac{75}{112}$
$\frac{-3t}{1} = \frac{75}{112}$
I am going to use cross multiplication. 
$112(-3t) = 1(75)$
$-336t = 75$
Dividing both sides by -336. 
$\frac{-336t}{-336} = \frac{75}{-336}$
$t = - \frac{25}{112}$

Hope this may help you.