(3t - 1) (3t+1) = 0 pls write the standered form this quadratic equation by step by step
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Step-by-step explanation:
(3t-1) (3t+1)
Using identity(a+b) (a-b) – (a-b) ²
yet (3t-1)²– 0 { (a-b)² a²+b²-2ab}
9t +1 -6t — 0
3t — -1
t — -1/3
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