Question

(3t+1) (3t+4) solve this ​

Answer 1

Answer:

9t^2+15t+4

Step-by-step explanation:

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Answer 2

Answer:

answer is

$9 {t}^{2} + 15t + 4$

Step-by-step explanation:

using identity:

$(x + a)(x + b) = {x}^{2} + (a + b)x \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: + ab$

now comparing given equation with above identity we get x=3t ,a=1 and b=4

now putting values in identity

$(3t + 1)(3t + 4)$

$= {(3t)}^{2} + (1 + 4)3t \: + 1 \times 4$

$= 9 {t}^{2} + 15t + 4$

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