Question

(3t-2)/3+(2t+3)/3=t+ 7/6
solve step by step in detail
cbsc board class 7 NCERT
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Answer 1

Step-by-step explanation:

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Answer 2

Answer:

(3t - 2)/3 + (2t + 3)/3 = t + 7/6

As denominators on left side are the same,

=> (3t - 2 + 2t + 3)/3 = t + 7/6

Taking L.C.M on right hand side,

=> (3t + 2t + 3 - 2)/3 = (6t + 7)/6

Now, multiply both sides by three. We get:

=> 3t + 2t + 3 - 2 = (6t + 7)/2

Now, Multiply both sides by two. So,

=> (5t + 1)2 = (6t + 7)

Now, open the brackets...

=> 10t + 2 = 6t + 7

=>( 10t + 2) + ( -2 ) = 6t + 7 - 2

=> 10t = 6t + 5

=> 10t - 6t = 6t + 5 - 6t

=> 4t = 5

Divide both sides by 4

=> t = 5/4

Therefore, t is equal to 5/4 (or) 1.25