Question

(3t-2)/4-(2t+3)/3=2/3-t​

Answer 1

Given

(3t-2)/4-(2t+3)/3=2/3-t

Now by taking L.C.M for 4 and 3 is 12

(3(3t-2)-4(2t+3))/12=2/3-t

By transposing the above equation we can write as

(9t-6-8t-12)/12=2/3-t

Again by transposing

t=26/13

t=2

Answer 2

Answer:

21t-t^2=78

Step-by-step explanation:

(3t-2/4)-(2t+3/3)=2/3-t

or,t-18/12=2/3-t

or,(t-18)(3-t)=24

or,21t-t^2=78(ans)