Question

3t-2/4-2t+3/3=2/3-t​

Answer 1

$\huge\pink{\boxed{\blue{\boxed{ \purple{ \boxed{{\pink{Answer}}}}}}}} \\ \large\pink{\boxed{\blue{\boxed{ \purple{ \boxed{{\pink{Your~answer↓}}}}}}}}$

$\large\bold\green{♧Solve :- \: \frac{3t - 2}{4} - \frac{2t + 3}{3} = \frac{2}{3} - t }$

$\large\bold\red{♧Solution♧}$

$\frac{3t - 2}{4} - \frac{2t + 3}{3} = \frac{2}{3} - t \\\large\bold\red{♧on \: taking \: lcm♧} \\ = > \frac{3(3t - 2) - 4(2t + 3)}{12} = \frac{2 - 3t}{3} \\ \small\bold\red{ = > } \: \frac{9t - 6 - 8t - 12}{12} = \frac{2 - 3t}{3} \\ \small\bold\red{ = > } \: \frac{t - 18}{4} = 2 - 3t \\ = > \: t - 18 = 8 - 12t \\ = > \: 13t \: = 26 \\ = > \: t = \frac{26}{13} \\ = > \: t \: = 2$

$\large\bold\green{♧verification♧}$

Consider LHS

$\: \frac{3t - 2}{4} - \frac{2t + 3}{3} \\ \small\bold\red{♧ \: put \: t \: = 2 \: ♧} \\ = \frac{3 \times 2 - 2}{4} - \frac{2 \times 2 + 3}{3} \\ = \frac{6 - 2}{4} - \frac{4 + 3}{3} = \frac{ 4}{4} - \frac{7}{3} \\ = 1 - \frac{7}{3} \\ = \frac{ 3 - 7}{3} \\ = - \frac{4}{3} \\ = - \frac{4}{3}$

Consider RHS

$\frac{2}{3} - t \\ \small\bold\red{♧ \: put \: t \: = 2 \: ♧} \\ = \frac{2}{3} - 2 \\ = \frac{2 - 6}{2} \\ = - \frac{4}{3}$

$\large\bold\red{ = > \: LHS = RHS}$

$\large\bold\blue{Hence \: verified}$

$\huge \fcolorbox{black}{cya}{♛Hope it helps U♛}$

Answer 2

Answer:

LHS = RHS....................