3t-2/4 - 2t+3/3 =2/3-t
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[3t-2] / 4 - [2t+3] / 3 = 2/3 - t
LCM of the denominators 3 and 4 is 12.
{[3(3t-2)] - [4(2t+3) ] }/12=2/3- t
9t-6-8t-12= 12 (2/3 -t) (solving the brackets)
9t-8t-18= 24/3- 12t
t-18= 8-12t
t+12t = 8+18
[Transposing 12t to LHS & 18 to RHS]
13t= 26
t=2.
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