Question

3t-2/4 - 2t+3/3 = 2/3 - t please solve my question I will mask as brainliest​

Answer 1

Answer:

2

Step-by-step explanation:

[3t-2] / 4 - [2t+3] / 3 = 2/3 - t

LCM of the denominators 3 and 4 is 12.

{[3(3t-2)] - [4(2t+3) ] }/12=2/3- t

9t-6-8t-12= 12 (2/3 -t) (solving the brackets)

9t-8t-18= 24/3- 12t

t-18= 8-12t

t+12t = 8+18

[Transposing 12t to LHS & 18 to RHS]

13t= 26

t=2.

Answer 2

Solution :

$\bf{\red{\underline{\bf{Given\::}}}}$

$\sf{\dfrac{3t-2}{4} -\dfrac{2t+3}{3} =\dfrac{2}{3} -t}$

$\bf{\red{\underline{\bf{To\:find\::}}}}$

The value of t.

$\bf{\red{\underline{\bf{Explanation\::}}}}$

$\mapsto\sf{\sf{\dfrac{3t-2}{4} -\dfrac{2t+3}{3} -\dfrac{2}{3} +t=0}}\\\\\\\mapsto\sf{3(3t-2)-4(2t+3)-4\times 2+12t=0\:\:\:\:[\therefore L.C.M=12]}\\\\\\\mapsto\sf{9t-6-8t-12-8+12t=0}\\\\\\\mapsto\sf{9t-8t+12t-6-8-12=0}\\\\\\\mapsto\sf{13t-26=0}\\\\\\\mapsto\sf{13t=26}\\\\\\\mapsto\sf{t=\cancel{\dfrac{26}{13} }}\\\\\\\mapsto\sf{\pink{t=2}}$

Thus;

The value of t is 2 .