3t-2/4-2t+3/3=2/3-t what is the solution???
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Given (3t − 2)/4 − (2t + 3)/3 = 2/3 − t
Now by taking L.C.M for 4 and 3 is 12
(3 (3t − 2) − 4 (2t+3) )/ 12 = 2/3 − t
By transposing the above equation we can write as
(9t −6 − 8t − 12)/12 =2/3 − t
t + 12t = 8 + 18
Again by transposing
t = 26/13
t = 2
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