3t-2/4-2t+3/3=2/3-t with equation
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LCM of the denominatos 3and 4 is 12
{3(3t-2)} - [4(2t+3)] /12=2/3-t
9t-6-8t-12=12(2/3-t) (solving brackets)
9t-8t-18=24/3-12
t-18=8-12t
t+12t = 8+18
13t=26
t=2
{3(3t-2)} - [4(2t+3)] /12=2/3-t
9t-6-8t-12=12(2/3-t) (solving brackets)
9t-8t-18=24/3-12
t-18=8-12t
t+12t = 8+18
13t=26
t=2
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