Question

(3t-2)/4 - (2t+3)/3 + t = 2/3

Answer 1

[3t-2] / 4 - [2t+3] / 3 = 2/3 - t

LCM of the denominators 3 and 4 is 12.

{[3(3t-2)] - [4(2t+3) ] }/12=2/3- t

9t-6-8t-12= 12 (2/3 -t) (solving the brackets)

9t-8t-18= 24/3- 12t

t-18= 8-12t

t+12t = 8+18

[Transposing 12t to LHS & 18 to RHS]

13t= 26

t=2.

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Answer 2

Answer:   t = 2.

Step-by-step explanation:

$\frac{3t-2}{4} - \frac{2t+3}{3} + t = \frac{2}{3}$

$\frac{3(3t-2)-4(2t+3)+12t}{12}$  =   $\frac{2}{3}$

9 t  -   6 - 8 t - 12 + 12 t  = $\frac{2}{3}$  ×  12    

13 t  -   18  = 2 × 4

13 t  - 18 = 8

13 t = 8 +  18

13 t  = 26  

t  =  $\frac{26}{13}$

t  =  2