3t-2 upon 3+2t+3 upon 2 is equal to t+7 upon 6
Answers
Answer:
2/11
Step-by-step explanation:
As per the provided information in the given question, we have :
We've to solve this equation i.e, we have to find out the value of t.
Basically, this question can be solved using the cross-multiplication method and transposition method.
In cross-multiplication method, we cross multiply the values. Here, firstly we'll simplify the L.H.S. In transposition method, we transpose the values from LHS to RHS and vice-versa and changing the arithmetic operator to calculate the value of the unknown value.
Taking the LCM in LHS and solving further using the fractions rules.
Performing multiplication using the multiplication over addition property.
Combining the like terms in the numerator of the LHS.
Performing cross multiplication.
Once again, performing multiplication using the multiplication over addition property as we did in the earlier step.
Transposing the like terms from LHS to RHS and vice-versa.
Performing subtraction in both sides.
Now, transposing 66 from LHS to RHS.
Therefore, the value of t is 2/11.
3t-2 upon 3+2t+3 upon 2 is equal to t+7 upon 6
= 3t-2/3 + 2t+3/2 = t+7/6
= 6t-4+6t+9/6= 6t+7/6
Lcm of 6 both sides
= 12t+5/6= 6t+7/6
Multiplying both 6 and 6
6× 12t+5/6 = 6× 6t+7/6
12t + 5 = 6t+7
= 12t-6t = 7-5 ( tranceposing 6t to LHS and 5 to RHS)
6t = 2
t = 2/6
cut 2 and 6
= 1/3 Answer