Question

3t-4/4-2t+3/3=2/3-t​

Answer 1

Answer:

$\frac{3t - 4}{4} - \frac{2t + 3}{3} = \frac{2}{3 - t} \\ \frac{3t}{4} - \frac{4}{4} - \frac{2t}{3} + \frac{3}{3} = \frac{2}{3 - t} \\ \frac{3t}{4} - \frac{2t}{3} - 1 + 1 = \frac{2}{3 - t} \\ (3 - t)( \frac{9t - 8t}{12} ) = 2 \\ (3 - t)( \frac{t}{12} ) = 2 \\ 3t - {t}^{2} = 24 \\ {t}^{2} - 3t + 24 = 0 \\ find \ \: the \: factors$