3t³+5t²+5t+2 by t-2 (polyonamial division method)
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Answer:
(i) t
2
−3,2t
4
+3t
3
−2t
2
−9t−12
Remainder is 0, hence t
2
−3 is a factor of 2t
4
+3t
3
−2t
2
−9t−12
(ii) x
2
+3x+1,3x
4
+5x
3
−7x
2
+2x+2
Remainder is 0, hence x
2
+3x+1 is a factor of 3x
4
+5x
3
−7x
2
+2x+2
(iii) x
3
−3x+1,x
5
−4x
3
+x
2
+3x+1
Remainder is 2, hence x
3
−3x+1 is not a factor of x
5
−4x
3
+x
2
+3x+1
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