√3tan A = 3sin A then find the value sin A +cos A/sin A-Cos A
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Answer:
√3sin A/ cos A = 3 sin A
√3 1/cos A = 3
√3 / 3 = cos A
√3 / √3×√3 = cos A
since we can write 3 = √3×√3
cos A = 1/√3 = B/H
SO,
P = √2
THEREFORE
SIN A + COS A / SIN A - COS A
P/H + B/H / P/H- B/H
P+B
H
P-B
P+B
P-B
√2 + 1
√2-1
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