√3tan tetha = 3sin tetha find the value of sin2tetha - cos2tetha
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√3 tantheta = 3 sin thetha
√3 sinthetha /costhetha = 3sintheta
√3 sinthEta/ 3sinthetha = costheta
1/√3 = costheta
cos square theta= 1/3
sin squaretheta +cos squaretheta =1
sin squaretheta = 1-1/3 = 2/3
sin square theta - cos square theta
2/3 - 1/3
1/3
√3 sinthetha /costhetha = 3sintheta
√3 sinthEta/ 3sinthetha = costheta
1/√3 = costheta
cos square theta= 1/3
sin squaretheta +cos squaretheta =1
sin squaretheta = 1-1/3 = 2/3
sin square theta - cos square theta
2/3 - 1/3
1/3
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