Question

3tan²30°+sec² 45°+tan²60°find the value

Answer 1

trigonometry

$3 \tan {}^{2} (30) + \sec {}^{2} (45) + \tan {}^{2} (60)$

$= 3 \times ( \frac{1}{ \sqrt{3} }) {}^{2} + ( \sqrt{2 } ) {}^{2} + (\sqrt{3} ) {}^{2}$

$= 1 + 2 + 3$

$= 6$

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