Question

(3tan45) (4sin60) - (2cos30) (3sin30)(3tan45) (4sin60) - (2cos30) (3sin30)

Answer 1

3×1×4×√3/2-2×√3/2×3×1/2×3×1×4×√3/2-2×√3/2×3×1/2=6√3-9-3√3/2=(12√3-18-3√3)/2=

(9√3-18)/2=9(√3-9)/2

Answer 2

Answer:

(3 × 1 )× (4 × √3 /2) - (2× √3/2 )×( 3 × 1/2)

= 3 × 2√3 - √3 × 3/2

= 6√3 - 3√3/2

= 12√6 - 3√3

= 24√3-3√3

= 21√3