Question

3tana=√3,then find the value of acute angle a 30°

Answer 1

Answer :

$\tan( \alpha ) = \frac{ \sqrt{3} }{3 } \\ \: \: \: \: \: \: \: \: \: \: \: \: \: = \frac{ \sqrt{3} }{3} \times \frac{ \sqrt{3} }{ \sqrt{3} } = \frac{3}{3 \sqrt{3} } \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: = \frac{1}{ \sqrt{3} } \\ \tan30 = \frac{1}{ \sqrt{3} } \\ \alpha = 30$

Hence proved . Please mark brainliest answer

Answer 2

hi this may help you