3tanc=4 then cosA, tanA and cotA
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Given:
3tanA =4
Therefore,
tanA = 4/3..........(1)
To Find:
1) cosA=?
2) tan A=?
3) cotA=?
Solution:
Here, tan A=4/3.......(From (1))
Now, cotA= 1/tanA
cotA=1/4/3
cotA=3/4
1+tan²A=cot²A.....(Identity)
By substituting the values,
1+(4/3) ²=cos²A
1+16/9=cos²A
cos²A=9/16/9
cos²A=25/9
cosA=5/3
Therefore,
(1) cosA=5/3
(2) tanA=4/3
(3) cotA= 3/4
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