Question

3tanx=0 then value of 2sinx+4 is​

Answer 1

Answer:

Now,

2sinx+tanx=0

or, 2sinx+

cosx

sinx

=0

or, sinx(2+secx)=0

or, sinx=0, cosx=−

2

1

or, x=nπ, x=(2kπ±

3

2π

), n,k∈I

or, x=nπ, x=(3k±1)

3

2π

, n,k∈I.