Question

3theta = 3sin theta - 4sin^2 theta
$\sin30 = 3 \sin0 - 4 { \sin }^{2} 0$
please refresh 0 as thita​

Answer 1

Answer:

Now, LHS=sin3(30o)=sin90o=1

Now, RHS=3sinθ−4sin3θ=3sin30o−4sin330o=3(21)−4(21)3=23−21=1

∴ LHS=RHS

Hence proved