3W-7/5W^3 ÷ 21-9W/27W Algebraic Fraction. Please solve quickly
Answers
Answer:
(1): "w3" was replaced by "w^3".
STEP
1
:
w
Simplify ——
21
Equation at the end of step
1
:
7 w
(3w-(((—•(w3))•27)•——))-9w
5 21
STEP
2
:
7
Simplify —
5
Equation at the end of step
2
:
7 w
(3w - (((— • w3) • 27) • ——)) - 9w
5 21
STEP
3
:
Equation at the end of step 3
7w3 w
(3w - ((——— • 27) • ——)) - 9w
5 21
STEP
4
:
Rewriting the whole as an Equivalent Fraction :
4.1 Subtracting a fraction from a whole
Rewrite the whole as a fraction using 5 as the denominator :
3w 3w • 5
3w = —— = ——————
1 5
Equivalent fraction : The fraction thus generated looks different but has the same value as the whole
Common denominator : The equivalent fraction and the other fraction involved in the calculation share the same denominator
Adding fractions that have a common denominator :
4.2 Adding up the two equivalent fractions
Add the two equivalent fractions which now have a common denominator
Combine the numerators together, put the sum or difference over the common denominator then reduce to lowest terms if possible:
3w • 5 - (9w4) 15w - 9w4
—————————————— = —————————
5 5
Equation at the end of step
4
:
(15w - 9w4)
——————————— - 9w
5
mark as brainliest plzzzzz n follow me