Math, asked by ali4558, 7 months ago

3W-7/5W^3 ÷ 21-9W/27W Algebraic Fraction. Please solve quickly

Answers

Answered by afsanaatia88
3

Answer:

(1): "w3" was replaced by "w^3".

STEP

1

:

w

Simplify ——

21

Equation at the end of step

1

:

7 w

(3w-(((—•(w3))•27)•——))-9w

5 21

STEP

2

:

7

Simplify —

5

Equation at the end of step

2

:

7 w

(3w - (((— • w3) • 27) • ——)) - 9w

5 21

STEP

3

:

Equation at the end of step 3

7w3 w

(3w - ((——— • 27) • ——)) - 9w

5 21

STEP

4

:

Rewriting the whole as an Equivalent Fraction :

4.1 Subtracting a fraction from a whole

Rewrite the whole as a fraction using 5 as the denominator :

3w 3w • 5

3w = —— = ——————

1 5

Equivalent fraction : The fraction thus generated looks different but has the same value as the whole

Common denominator : The equivalent fraction and the other fraction involved in the calculation share the same denominator

Adding fractions that have a common denominator :

4.2 Adding up the two equivalent fractions

Add the two equivalent fractions which now have a common denominator

Combine the numerators together, put the sum or difference over the common denominator then reduce to lowest terms if possible:

3w • 5 - (9w4) 15w - 9w4

—————————————— = —————————

5 5

Equation at the end of step

4

:

(15w - 9w4)

——————————— - 9w

5

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