Question

3x^0-1/3x^0+1 plzz can anyone help me with this sum

Answer 1

$\red{ Value \: of \: \frac{3x^{0} - 1}{3x^{0}+1}}$

$= \frac{3\times 1- 1}{3\times 1 +1}$

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/* By Exponential Law */

a⁰ = 1

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$= \frac{ 3-1}{3+1}$

$= \frac{2}{4}$

$= \frac{1}{2}$

Therefore.,

$\red{ Value \: of \: \frac{3x^{0} - 1}{3x^{0}+1}}\green {= \frac{1}{2}}$

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Answer 2

$\bf{\underline{\underline{\bigstar\bigstar \: To \: Find : }}}$

$\:\:\:$

• $\footnotesize{ \dfrac{{3x}^{0} - 1}{{3x}^{0} + 1}}$

$\:\:\:$

$\bf{\underline{\underline{\bigstar\bigstar \: Some \: information : }}}$

$\:\:\:$

• if a no. has power 0 then its value is always 1

$\:\:\:$

$\bf{\underline{\underline{\bigstar\bigstar \: Solution : }}}$

$\:\:\:$

$\footnotesize{ \dfrac{{3x}^{0} - 1}{{3x}^{0} + 1}}$

$\footnotesize{\implies \dfrac{(3 \times 1) - 1}{(3 \times 1) + 1}}$

$\footnotesize{\implies \dfrac{3 - 1}{ 3 + 1}}$

$\footnotesize{\implies \dfrac{2}{4}}$

$\footnotesize{\implies \cancel{\dfrac{2}{4}}}$

$\footnotesize{\implies \dfrac{1}{2}}$

$\:\:\:$

$\bold{\footnotesize{Value \: of \: \dfrac{{3x}^{0} - 1}{{3x}^{0} + 1} = \dfrac{1}{2}}}$