Question

(3x+1)\16+(2x-3)\7=(x+3)\8+(3x-1)\14

Answer 1

answer is x=11 as there are is no x^2 terms

Answer 2

(3x+1)/16 + (2x-3)/7 = (x+3)/8 + (3x-1)/14
(3x+1)/16 - (x+3)/8 = (3x-1)/14 - (2x-3)/7
making denominator equal

(3x+1)/16 - 2(x+3)/2×8 = (3x-1)/14 - 2(2x-3)/2×7
(3x+1)/16 - (2x+6)/16 = (3x-1)/14 - (4x-12)/14
(3x+1-2x-6)/16 = (3x-1-4x+12)/14
(x-5)/16 = (11-x)/14
14(x-5) = 16(11-x). cross multiply
14x-70 = 176-16x
30x = 246
x = 246/30 => 41/5

hope this helps