Question

(3x + 1)²-(3x+2) (3x-1) I want full method step by step​

Answer 1

Answer:

$\qquad\sf {:}\rightarrowtail (3x+1)^2-(3x+2)(3x-1)$

$\qquad\sf {:}\rightarrowtail (3x^2+2.3x.1+1^2)-\left\{3x(3x-1)+2(3x-1)\right\}$

$\qquad\sf {:}\rightarrowtail (9x^2+6x+1)-(9x^2-3x+6x-2)$

$\qquad\sf {:}\rightarrowtail 9x^2+6x+1-9x^2+3x-6x+2$

$\qquad\sf {:}\rightarrowtail 9x^2-9x^2+6x-3x+1+2$

$\qquad\sf {:}\rightarrowtail 3x+3$

$\qquad\sf {:}\rightarrowtail 3(x+1)$

Answer 2

$(3x + 1) {}^{2} - (3x + 2)(3 x - 1) \\ 3x {}^{2} + 1 {}^{2} + 2(3x)(1) - (3x + 2)(3x) - (3x + 2)( - 1) \\ 3x {}^{2} + 1 + 6x - 6x + 6x + 3x + 2 \\ - 6x + 6x \: will \: be \: canclied \\ 3x {}^{2} + 9x + 3 \\ by \: factrization \\ 3(x {}^{2} + 3x + 1)$