Math, asked by shashwatee, 20 days ago

(3x-1)^2 = 5(x+8)


want genuine answers​

Answers

Answered by surajjayaswal2007
1

Answer:

(3x-1)²=5x+40

using identity 2nd

(a-b)²=a²-2ab+b²

9x²-6x+1=5x+40

9x²+6x-5x=40-1

9x²+x= 39

x²+x= 39/9

here is your answer

hope it helps you

Answered by praptipradhan21
1

Answer:

Step-by-step explanation:

(3x-1)^2=5(x+8)

(3x)²+1²-(2*3x*1)=5x+(5*8)

9x²+1-6x=5x+40

9x²+1-6x-5x-40=0

9x²-11x-39=0

x=−b±b2−4ac−−−−−−−√2a

x=−(−11)±(−11)2−4(9)(−39)−−−−−−−−−−−−−−−−√2(9)

x=11±121−−1404−−−−−−−−−−√18

x=11±1525−−−−√18

x=11±561−−√18

x=1118±561−−√18

x=2.78062

 

x=−1.5584

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