(3x-1)^2 = 5(x+8)
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Answered by
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Answer:
(3x-1)²=5x+40
using identity 2nd
(a-b)²=a²-2ab+b²
9x²-6x+1=5x+40
9x²+6x-5x=40-1
9x²+x= 39
x²+x= 39/9
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Answered by
1
Answer:
Step-by-step explanation:
(3x-1)^2=5(x+8)
(3x)²+1²-(2*3x*1)=5x+(5*8)
9x²+1-6x=5x+40
9x²+1-6x-5x-40=0
9x²-11x-39=0
x=−b±b2−4ac−−−−−−−√2a
x=−(−11)±(−11)2−4(9)(−39)−−−−−−−−−−−−−−−−√2(9)
x=11±121−−1404−−−−−−−−−−√18
x=11±1525−−−−√18
x=11±561−−√18
x=1118±561−−√18
x=2.78062
x=−1.5584
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