Question

(3x+1)^2+6x=0, find x or y if possible. Thank you to anyone willing to help!

Answer 1

Answer:

9x^2+6x+1+6x=0

9x^2+12x+1=0

by formula, x= -b±√(b²-4ac))/(2a)

x= (-12±√(12^2-4*9*1))/2*9

x= (-12±√108)/18

x= (-12/18)±(√108/18)

x= (-2/3)±(6√3/18)

x= (-2/3)±(1/√3)

therefore,

x=(-2/3)+(1/√3) or x=(-2/3)-(1/√3)

Answer 2

Answer:

48, -48 is the answer to your question