Question

(3x-1/2x)^2 please write in standard form

Answer 1

hello mate.......

given......

$(3x - \frac{1}{2x} ) {}^{2} \\ \\ = > 9x {}^{2} + \frac{1}{4x {}^{2} } - \frac{6x}{2x} \\ \\ = > 9x {}^{2} + \frac{1}{4x {}^{2} } - 3$

Hope it helps you......

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Answer 2

solution:-

=> (3x-1/2x)²

so, first

=> (3x-1)²

= 9x² - 1

now,

=> 9x² - 1 / (2x) ²

=> 9x²-1 /4x²

9x²-1 = 4x²

I hope it helps you...