Math, asked by RockingBand2009, 6 months ago

3x-1/3=2(x-1/2)+5
pls answer

Answers

Answered by Anonymous
2

Answer:

Multiply the numbers

3

1

1

3

=

2

(

1

1

2

)

+

5

3x{\color{#c92786}{-1}} \cdot {\color{#c92786}{\frac{1}{3}}}=2(x-1 \cdot \frac{1}{2})+5

3x−1⋅31=2(x−1⋅21)+5

3

1

3

=

2

(

1

1

2

)

+

5

3x{\color{#c92786}{-\frac{1}{3}}}=2(x-1 \cdot \frac{1}{2})+5

3x−31=2(x−1⋅21)+5

2

Multiply the numbers

again

3

1

3

=

2

(

1

1

2

)

+

5

3x-\frac{1}{3}=2(x{\color{#c92786}{-1}} \cdot {\color{#c92786}{\frac{1}{2}}})+5

3x−31=2(x−1⋅21)+5

3

1

3

=

2

(

1

2

)

+

5

3x-\frac{1}{3}=2(x{\color{#c92786}{-\frac{1}{2}}})+5

3x−31=2(x−21)+5

3

Distribute

3

1

3

=

2

(

1

2

)

+

5

3x-\frac{1}{3}={\color{#c92786}{2(x-\frac{1}{2})}}+5

3x−31=2(x−21)+5

3

1

3

=

2

1

+

5

3x-\frac{1}{3}={\color{#c92786}{2x-1}}+5

3x−31=2x−1+5

4

Add the numbers

3

1

3

=

2

1

+

5

3x-\frac{1}{3}=2x{\color{#c92786}{-1}}+{\color{#c92786}{5}}

3x−31=2x−1+5

3

1

3

=

2

+

4

3x-\frac{1}{3}=2x+{\color{#c92786}{4}}

3x−31=2x+4

5

Add

1

3

\frac{1}{3}

31

to both sides of the equation

3

1

3

=

2

+

4

3x-\frac{1}{3}=2x+4

3x−31=2x+4

3

1

3

+

1

3

=

2

+

4

+

1

3

3x-\frac{1}{3}+{\color{#c92786}{\frac{1}{3}}}=2x+4+{\color{#c92786}{\frac{1}{3}}}

3x−31+31=2x+4+31

6

Simplify

Add the numbers

Add the numbers

again

3

=

2

+

1

3

3

3x=2x+\frac{13}{3}

3x=2x+313

7

Subtract

2

2x

2x

from both sides of the equation

3

=

2

+

1

3

3

3x=2x+\frac{13}{3}

3x=2x+313

3

2

=

2

+

1

3

3

2

3x{\color{#c92786}{-2x}}=2x+\frac{13}{3}{\color{#c92786}{-2x}}

3x−2x=2x+313−2x

8

Simplify

Combine like terms

Multiply by 1

Combine like terms

=

1

3

3

x=\frac{13}{3}

x=313

Solution

=

1

3/3

Step-by-step explanation:

Mark me as brainliest answer

Answered by nikitakaushik358
1

Answer:

i hope it will help you out

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