Question

(3x-1)^3 in differentiation

Answer 1

$\frac{d}{dx} ({3x - 1})^{3} \\ = 3( {3x - 1})^{2} \frac{d}{dx} (3x - 1) \\ = 3( {3x - 1})^{2} 3 \\ = 9( {3x - 1})^{2}$