(3x+1)³+(x-3)³+(4-2x)³-6(3x+1)(x-3)(x-2)=0 than find the value x
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value of x = -1
Before going to solve, let's know some important formula regarding the same.
if a + b + c = 0 then a³ + b³ + c³ - 3abc = 0
here given, (3x + 1)³ + (x - 3)³ + (4 - 2x) + 6(3x + 1)(x - 3)(x - 2) = 0
⇒(3x + 1)³ + (x - 3)³ + {-2(x - 2)}³ -3(3x + 1)(x - 3){-2(x - 2)} = 0
we see it follows a³ + b³ + c³ - 3abc = 0
then must be a + b + c = 0
⇒(3x + 1) + (x - 3) + {-2(x - 2)} = 0
⇒3x + 1 + x - 3 + 4 - 2x = 0
⇒2x + 2 = 0
⇒x = -1
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Divide ( 3x^4+5x^3-7x^2+2x+2) by (x^2+3x+1).
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