Math, asked by dishasatija, 1 year ago

(3x-1/3x)²-(3x+1/3x)(3x-1/3x)

Answers

Answered by Anonymous
24
Its of the form:
(a-b)^2 - (a+b)*(a-b)
= a^2 + b^2 - 2*a*b -(a^2 - b^2)
= a^2 + b^2 - 2*a*b -a^2 + b^2
= 2b^2 - 2*a*b = 2*b*[b - a]
ATQ,
a = 3x, b = 1/3x
2*b*[b-a] = 2*1/3x*[1/3x - 3x] = 2/3x*[(1- 9x^2)/3x] = 2*[1-9x^2]/9x^2 
Ans: 2*[1-9x^2]/9x^2      OR      2*[(1-3x)*(1+3x)]/9x^2     OR       " 2/9x^2 - 2 "
Hope it helps.
Answered by Anonymous
6

refer to the attached image for the answer

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