Math, asked by ratheeanju80, 9 months ago

(3x-1/3x)^2-(3x+1/3x)(3x-1/3x) simply and state the formula used​

Answers

Answered by pooja828
4

Answer:

x=3

Step-by-step explanation:

(3x-1/3x)2 - (3x+1/3x)(3x-1/3x)

w.k.t,

(a-b)2= (a)2-2(a)(b)+(b)2

and (a-b) (a+b) = a2-b2

(3x)2-2(3x)(1/3x)-3x2-1/3x2

9x2-1/3x2-1/9x2-3x2-1/3x2

9x2 2/9x2-3x2-1/3x2

6x2-5/9x2

6x2-5x2=9

x2=9

x= √9

x=3

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Answered by acsahjosemon40
1

Answer:

x=3

Step-by-step explanation:

(3x-1/3x)2 - (3x+1/3x)(3x-1/3x)

w.k.t,

(a-b)2= (a)2-2(a)(b)+(b)2

and (a-b) (a+b) = a2-b2

(3x)2-2(3x)(1/3x)-3x2-1/3x2

9x2-1/3x2-1/9x2-3x2-1/3x2

9x2 2/9x2-3x2-1/3x2

6x2-5/9x2

6x2-5x2=9

x2=9

x= √9

x=3

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