(3x+1) (3x-8) using identities
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0
Answer:
ANSWER
Suitable identity is (x+a)(x+b)=x
2
+(a+b)x+ab
(3x+4)(3x−5)=(3x)
2
+(+4−5)3x+(4×−5)
9x
2
+(−1)3x+(−20)
9x
2
−3x−20
Answered by
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Answer:
use identity
(x+a)(x+b)=x^2+(a+b)x+ab
=(3x) ^2+(1-8)*3x+(-8)
=9x^2-21x-8
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