Question

(3x-1) (4x³-2x²+6x-3) solve​

Answer 1

Answer:

Step-by-step explanation:

we have to find quotient and remainder when 4x³ + 2x² + 5x - 6 is divided by 2x² + 3x + 1.

so, Let's start to divide !

2x² + 3x + 1 ) 4x³ + 2x² + 5x - 6(2x -2

4x³ + 6x² + 2x

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-4x² + 3x - 6

-4x² - 6x - 2

-------------------

9x - 4

hence quotient = 2x - 2

and remainder = 9x -

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Answer 2

Answer:

(3x-1)(4x³-2x²+6x-3)

= 12x⁴-6x³+18x²-9x-4x³+2x²-6x+3

= 12x⁴-10x³+20x²-15x+3: Ans

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