(3x-1) (4x³-2x²+6x-3) solve
Answers
Answered by
1
Answer:
Step-by-step explanation:
we have to find quotient and remainder when 4x³ + 2x² + 5x - 6 is divided by 2x² + 3x + 1.
so, Let's start to divide !
2x² + 3x + 1 ) 4x³ + 2x² + 5x - 6(2x -2
4x³ + 6x² + 2x
---------------------------
-4x² + 3x - 6
-4x² - 6x - 2
-------------------
9x - 4
hence quotient = 2x - 2
and remainder = 9x -
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Answered by
5
Answer:
(3x-1)(4x³-2x²+6x-3)
= 12x⁴-6x³+18x²-9x-4x³+2x²-6x+3
= 12x⁴-10x³+20x²-15x+3: Ans
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