Question

3x - 1/5 =2 - x
Solve the problem with check

Answer 1

Answer is x = 11/20

Hope it helps u....

Answer 2

Answer:

$\rm\dfrac{11}{20}$

Step-by-step explanation:

$\rm{3x - \dfrac{1}{5} = 2 - x}$

$\:$

$\implies \rm{3x - \dfrac{1}{5} + x = 2}$

$\:$

$\implies \rm{4x - \dfrac{1}{5} = 2}$

$\:$

$\implies \rm{4x = \dfrac{10 + 1}{5} }$

$\:$

$\implies \rm{4x = \dfrac{11}{5} }$

$\:$

$\implies \rm{x = \dfrac{11}{5} \div 4}$

$\:$

$\implies \rm{x = \dfrac{11}{5} \times \dfrac{1}{4} }$

$\:$

$\implies \rm{x = \dfrac{11 \times 1}{5 \times 4} }$

$\:$

$\implies\rm{\underline{\boxed{\rm{{x = \dfrac{11}{20} }}}}}$

$\:$

$\:$

Checking

Putting x = $\rm\dfrac{11}{20}$ on LHS, we get

$\:$

$\rm{3 \times \dfrac{11}{20} - \dfrac{1}{5} = \dfrac{3 \times 11}{20} - \dfrac{1}{5} }$

$\:$

$\rm = {\dfrac{33}{20} - \dfrac{1}{5} = \dfrac{33}{20} - \dfrac{1 \times 4}{5 \times 4} }$

$\:$

$\rm{ = \dfrac{33}{20} - \dfrac{4}{20} = \dfrac{33 - 4}{20} }$

$\:$

$\rm{ = \dfrac{29}{20}.}$

$\:$

Putting x = $\rm\dfrac{11}{20}$ on RHS, we get

$\:$

$\rm{2 - \dfrac{11}{20} = \dfrac{2}{1} - \dfrac{11}{20}}$

$\:$

$\rm{ = \dfrac{2 \times 20}{1 \times 20} - \dfrac{11}{20} = \dfrac{40}{20} - \dfrac{11}{20} }$

$\:$

$\rm{ = \dfrac{40 - 11}{20} }$

$\:$

$\rm{ = \dfrac{29}{20}.}$

Since,

$\dfrac{29}{20} = \dfrac{29}{20}$

Therefore,

$\rm{LHS = RHS} \:$

Hence, checked! ✓.

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