Question

3x + 1 over 4y2 What is the value of the expression above when x = 3 and y = 4?

Answer 1

$If \: x = 3 \: and \: y = 4 , then \\</p><p>the \: value \: of \: 3x + \frac{1}{4y^{2}}$

$= 3 \times 3 + \frac{ 1} { 4 \times 4^{2}}\\= 9 + \frac{1}{4 \times 16 }\\= 9 + \frac{1}{64} \\= \frac{ 576+1}{64} \\= \frac{577}{64}$

Therefore.,

$\red {value \: of \: 3x + \frac{1}{4y^{2}}}\green {= \frac{577}{64}}$

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