Math, asked by bhartitanya342, 1 month ago

(3x-1) square-(3x-2)(3x+1)​

Answers

Answered by AyushmanAryan
1

Answer:

3-3x

Step-by-step explanation:

(3x-1)^2-(3x-2)(3x+1)

=(3x)^2+1^2-2(3x)(1)-(3x-2)(3x+1)

=9x^2+1-6x-(9x^2+3x-6x-2)

=9x^2+1-6x-9x^2-3x+6x+2

=3-3x

Thanku

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