(3x-1) square-(3x-2)(3x+1)
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Answer:
3-3x
Step-by-step explanation:
(3x-1)^2-(3x-2)(3x+1)
=(3x)^2+1^2-2(3x)(1)-(3x-2)(3x+1)
=9x^2+1-6x-(9x^2+3x-6x-2)
=9x^2+1-6x-9x^2-3x+6x+2
=3-3x
Thanku
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