(3x+1) (X+1) what is its derivatives
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1
Answer:
ANSWER
Let f(x)=
x+1
2
−
3x−1
x
2
f
′
(x)=
dx
d
(
x+1
2
)−
dx
d
(
3x−1
x
2
)
By quotient rule
f
′
(x)=[
(x+1)
2
(x+1)
dx
d
(2)−2
dx
d
(x+1)
]−[
(3x−1)
2
(3x−1)
dx
d
(x
2
)
dx
d
(3x−1)
]
=[
(x+1)
2
(x+1)(0)−2(1)
]−[
(3x−1)
2
(3x−1)(2x)−(x
2
)(3)
]
=
(x+1)
2
−2
−[
(3x−1)
2
6x
2
−2x−3x
2
]
=
(x+1)
2
−2
−[
(3x−1)
2
3x
2
−2x
]
=
(x+1)
2
−2
−
(3x−1)
2
x(3x−2)
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