Question

3x-1/x =2 by formula method
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Answer 1

You have to solve this using the 'discriminant' method.

x2−3x+1=0

Considering the coefficients and constants in the equation

a=1 [Coefficient of x2 ]

b= -3 [Coefficient of x ]

c = 1 [The constant term]

The formula for the discriminant of a quadratic equation is

D=b2−4ac

Substituting values for a, b and c

D=(−3)2−4∗1∗1

D=9−4

D=5

Now, the formula for finding 'x' using the discriminant is

x = ( −b±√D)/2a

Substituting values for b, D and a in the above formula, you get

x = (3±√5)/2

Hence, the values for 'x' are

x = (3+√5)/2 and (3−√5)/2

...

hope it helps ...

Answer 2

Answer:

Step-by-step explanation:

x2−3x+1=0

Considering the coefficients and constants in the equation

a=1 [Coefficient of x2 ]

b= -3 [Coefficient of x ]

c = 1 [The constant term]

The formula for the discriminant of a quadratic equation is

D=b2−4ac

Substituting values for a, b and c

D=(−3)2−4∗1∗1

D=9−4

D=5

Now, the formula for finding 'x' using the discriminant is

x = ( −b±√D)/2a

Substituting values for b, D and a in the above formula, you get

x = (3±√5)/2

Hence, the values for 'x' are

x = (3+√5)/2 and (3−√5)/2

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