Question

(3x+1/x)^3
expand using formulae​

Answer 1

Answer:

27x^3 + 1 / x^3 + 27x + 9/x

Step-by-step explanation:

Formula used :

 ( a + b )^3 = a^3 + b^3 + 3ab( a + b )

Here,

⇒ ( 3x + 1 / x )^3

⇒ (3x)^3 + (1/x)^3 + 3(3x*1/x)(3x+1/x)

⇒ 27x^3 + 1 / x^3 + 3(3*1)(3x+1/x)

⇒ 27x^3 + 1 / x^3 + 9(3x+1/x)

⇒ 27x^3 + 1 / x^3 + 27x + 9/x

Therefore, ( 3x + 1 / x )^3 = 27x^3 + 1 / x^3 + 27x + 9 / x

Answer 2

Answer:

thisa is answer in atachment up one who answered in wrong he dont known anything i have app called rank guru for cbse text book and answers for 8th is stu 1461 and pass4209