Question

3x-1/(x-4)(x+1)(x-1) resolve in the partial fraction . please guys
give me the step by step solution . ​

Answer 1

please tell me the answer

Answer 2

Answer:

3x−1(x−4)(x+1)(x−1)=1115x−4+−25x+1+−13x−1

Step-by-step explanation:

Solution:

3x−1(x−4)(x+1)(x−1)=Ax−4+Bx+1+Cx−1

∴3x−1=A(x+1)(x−1)+B(x−4)(x−1)+C(x−4)(x+1)

Put x=4 to find A,

3(4)−1=A(4+1)(4−1)

∴11=15A

∴A=1115

Put x=−1 to find B,

3(−1)−1=B(−1−4)(−1−1)

∴−4=B(−5)(−2)

∴B=−25

Put x=1 to find C,

3(1)−1=C(1−4)(1+1) ∴2=C(−3)(2)

∴C=−13

∴3x−1(x−4)(x+1)(x−1)=1115x−4+−25x+1+−13x−1